Table of Contents

Goal

An opening statement

Technique

Talking

Original: The act of debating

Paraphrased: Arguing

In conclusion,

Goal

1. To demonstrate how vertical oscillation is affected by load

2. To find the spring constant

3. To calculate the spring’s effective weight

An opening

Let the force constant, i.e. the force to produce unit extension, be k. Let the force to create unit extension of the spring be k. After the spring has been released, the equation is in motion.

kx= -mx

Where x represents the acceleration towards equilibrium? =

Thus, the motion can be described as simple harmonic with periodic time T.

In conclusion,

it is evident that

Thus, T2 graph against straight line.

On first glance, it seems that the straight line must pass through the origin. But the actual experiment shows otherwise. This is because it has been overlooked that the spring’s effective mass (mo), should be known and written in the equation.

Stop watch, spiral spring, clamps, stands and clamps.

Procedure

1. The spring is suspended from a support. It is then loaded using slotted masses attached to the lower end. This allows it to be measured the time required for the suspension load to perform 20 vertical oscillations.

2. To obtain the oscillations mean time, repeat the timing twice more

3. For 20 oscillations, the load of 50g will be increased and then repeated.

4. Continue on until all five loads are taken.

5. The readings are recorded and then the results are compiled into the table.

A graph plotted with T2/s2 ordinates and corresponding m/kg

Calculate the slope from which l can be determined

T=0 when the magnitude m0 equals to be the negative load axis OC

DiscussionSpring constant refers to the force acting on a spring relative to its displacement. From the above calculation, we can calculate k=24. An amount that simplifies band structures by creating an analogy with the behavior of a freely moving particle with that mass, is called effective mass. You can calculate the effective mass by plotting graphs where x-intercept equals the effective mass. The graph yields the value for the spring’s effectual mass in kilograms.

ConclusionThe spring constant value, k=24. The effective spring mass, in kilograms.